Question

can someone help me please

Answer 1

                    Question # 1

Answer:

The surface area of the square pyramid is 44.84.

Step-by-step explanation:

As the perpendicular height = 3

square base side = 4

Using the formula to compute the surface area of the square pyramid:

$A=a^2+2a\sqrt{\frac{a^2}{4}+h^2}$

Here:

a = Base Edge = 4

h = height = 3

$A=4^2+2\left(4\right)\sqrt{\frac{4^2}{4}+3^2}$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$A=4^2+2\cdot \:4\sqrt{\frac{4^2}{4}+3^2}$

$A=4^2+8\sqrt{13}$         ∵  $2\cdot \:4\sqrt{\frac{4^2}{4}+3^2}=8\sqrt{13}$

$A=16+8\sqrt{13}$

$A=44.84$

Therefore, the surface area of the square pyramid is 44.84.

                       Question # 2

Answer:

The surface area of a cube is 37.5

Step-by-step explanation:

Given the the length of one of the sides = s = 2.5

To find the surface area of a cube, using the formula

$A=\:6s^2$

$A=\:6\left(2.5\right)^2$

$A=6\cdot \:6.25$          ∵ $2.5^2=6.25$

$A=37.5$

Therefore, the surface area of a cube is 37.5