Answer:
None of the given quadrilaterals. It's a trapezium (Irregular quadrilateral).
Step-by-step explanation:
Mark the points on a coordinate system (look at the picture).
We have the quadrilateral.
It's not a square.
It's not a rectangle.
It's not a rombus.
Maybe it's a trapezoid.
If it is a trapezoid, then the segments AC abd DB must be parallel.
If the segmets of a line are parallel, then they have the same slopes.
The formula of a slope:
[tex]m=\dfrac{y_2-y}{x_2-x_1}[/tex]
Substitute the coordintes of the points.
The slope of a segment AC:
A(8, -1), C(17, 4)
[tex]m_{AC}=\dfrac{4-(-1)}{17-8}=\dfrac{5}{9}[/tex]
The slope of a segment DB:
D(8, -4), B(13, -1)
[tex]m_{DB}=\dfrac{-1-(-4)}{13-8}=\dfrac{3}{5}[/tex]
[tex]m_{AC}\neq m_{DB}[/tex]
AC and CB are not parallel. Therefore its not a trapezoid.
