Question

April is an avid chess player. She sets up a coordinate system on her chess board so she can record
the position of the pieces during a game. In a recent game, April noted that her king was at (4,2) at
the same time that her opponent’s king was at (7,8). How far apart were the two kings? Round to
the nearest tenth of a unit if necessary.

Answer 1

Answer:

$6.7\ units$

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

(4,2) and (7,8)

substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(7-4)^{2}}$

$d=\sqrt{(6)^{2}+(3)^{2}}$

$d=\sqrt{45}\ units$

$d=6.7\ units$