Question

In ΔABC, AC = 4. What is the value of ED?

1
4
2
8

Answer 1

The value of ED is 2.

Solution:

Given ABC is a triangle and AC = 4

BE = EA = 2.7 and BD = DC = 2.43

It clearly shows that ED is the mid-segment of ΔABC.

By mid-segment theorem,

The segment connecting two points of the triangle is parallel to the third side and is half of that side.

⇒ ED || AC and $ED = \frac{1}{2}AC$

$\Rightarrow ED = \frac{1}{2}AC$

$\Rightarrow ED = \frac{1}{2}\times 4$

⇒ ED = 2

The value of ED is 2.