Question

Factor the expression.
q? -89 +12
© (q - 4)(9-3)
(6-4) (G - 2)
(q+6) (q+2)
(4-6) (q-2)​

Answer 1

Answer:

$\mathrm{Factor}\:q^2-8q+12:\quad \left(q-2\right)\left(q-6\right)$

Step-by-step explanation:

Considering the expression

$q^2-8q+12$

$\mathrm{Break\:the\:expression\:into\:groups}$

$=\left(q^2-2q\right)+\left(-6q+12\right)$

$\mathrm{Factor\:out\:}q\mathrm{\:from\:}q^2-2q\mathrm{:\quad }q\left(q-2\right)$

$=q\left(q-2\right)+\left(-6q+12\right)$

$\mathrm{Factor\:out\:}-6\mathrm{\:from\:}-6q+12\mathrm{:\quad }-6\left(q-2\right)$

$=q\left(q-2\right)-6\left(q-2\right)$

$\mathrm{Factor\:out\:common\:term\:}q-2$

$=\left(q-2\right)\left(q-6\right)$

Therefore,

$\mathrm{Factor}\:q^2-8q+12:\quad \left(q-2\right)\left(q-6\right)$