Answer:
Perpendicular equations: 1 and 2, 1 and 3
Parallel equations: 2 and 3
Step-by-step explanation:
The three equations are:
[tex]y=\frac{1}{2}x+5[/tex] ...Equation 1
[tex]y-3=-2(x+7)[/tex]
Expanding the bracket, we have,
[tex]y-3=-2x-14\\\\y=-2x-14+3\\\\y = -2x-11[/tex]
[tex]y=-2x-11[/tex] ...Equation 2
[tex]2x+y=9\\\\y = 9-2x\\\\[/tex]
[tex]y = -2x + 9[/tex] ...Equation 3
For two equations to be perpendicular, the product of their slopes must equals -1.
For two equations to be parallel, their slopes must be equal.
The equation of a straight line is: [tex]y=mx+c[/tex]
Where m = slope (or tangent) of the equation.
For equation 1, slope1 = 1/2
For equation 2, slope2 = -2
For equation 1, slope3 = -2
Slope1 * Slope 2 = [tex]\frac{1}{2}*-2=-1[/tex]
Therefore, equations 1 and 2 are perpendicular.
Slope 1 * Slope 3 = [tex]\frac{1}{2}*-2=-1[/tex]
Therefore, equations 1 and 2 are perpendicular.
Slope 2 = Slope 3 = -2
Therefore, equations 2 and 3 are parallel.