Question

PLEASE HELP: Line segment AB has endpoints A(-1.5, 0) and B (4.5, 8). Point C is on line segment AB and is located at (0, 2)

What is the ratio of AC/CB

Answer 1

Answer:

1:3

Step-by-step explanation:

We can note down the following base on the question.

A(-1.5, 0) ,B (4.5, 8) and C(0, 2).

Let find the length o AC and CB.

The distance formula is given by

$d = \sqrt{({x_2- x_1})^{2} +({y_2 - y_1})^{2} }$

This implies that

$dAC= \sqrt{({0- - 1.5})^{2} +({0- 2})^{2}}$

$\implies AC= \sqrt{{ 1.5}^{2} +(- 2)^{2}}$

$\implies AC= \sqrt{2.25 +4}$

$\implies AC= \sqrt{6.25 }$

$\implies AC= 2.5 units$

Also,

$CB = \sqrt{ {(4.5 - 0)}^{2} + ( {8 - 2)}^{2} }$

$\implies CB = \sqrt{ {4.5} ^{2} +{6}^{2} }$

$\implies CB = \sqrt{ 20.25 +36}$

$\implies CB = \sqrt{ 56.25}$

$\implies CB =7.5 units$

Therefore, the ratio of

$\frac{AC}{CB} = \frac{2.5}{7.5} = \frac{1}{3} = 1:3$