Question

or a population, N = 10,000, μ = 121, and σ = 21. Find to 2 decimal places the z value for










x¯=112.35
for n = 49

Answer 1

Answer:

The z value is - 2.88

Step-by-step explanation:

The formula of the z-score of a population is z = (x¯ - μ)/(σ/$\sqrt{n}$)

The given in the problem is:

• μ = 121
• σ = 21
• x¯ = 112.35
• n = 49

Let us substitute all of these values in the rule above

$z=\frac{112.35-121}{\frac{21}{\sqrt{49}}}$

Simplify up and down

$z=\frac{-8.65}{\frac{21}{7}}$

$z=\frac{-8.65}{3}$

z = - 2.883333

Round it to 2 decimal places

∴ z = - 2.88

The z value is - 2.88

Answer 2

The value of z is -2.88 and this can be determined by using the formula of the z-score and also by using the given data.

Given :

• $\bar{x} = 112.35$

• n = 49

• N = 10000

• $\mu = 121$

• $\sigma = 21$

To determine the value of z the below formula can be used:

$\rm z = \dfrac{\bar{x}-\mu}{\dfrac{\sigma}{\sqrt{n} }}$

Now, substitute the values of all known terms in the above formula in order to determine the value of 'z'.

$\rm z = \dfrac{112.35-121}{\dfrac{21}{\sqrt{49} }}$

Now, simplify the above expression.

$\rm z = \dfrac{-8.65}{\dfrac{21}{7 }}$

z = -2.883333

Given in the problem that the value of 'z' should be rounded up to two decimal places that is:

z = -2.88

For more information, refer to the link given below:

https://brainly.com/question/23017717