Answer:
33.15 square inches.
Step-by-step explanation:
Given:
Length of the minute hand is 11.25' from the center of the clock to the tip of the hand.
Question asked:
What is the area swept out by the minute hand as it moves 5 minutes of time?
Solution:
As length of the minute hand is '11.25' from the center of the clock to the tip of the hand means radius of the circle, r = 11.25 inches.
First of all we will find area of circle swept by the minutes hand,
[tex]Area\ of\ circle=\pi r^{2}[/tex]
[tex]=\frac{22}{7} \times11.25\times11.25\\\\ =\frac{2784.375}{7} \\ \\ =397.77\ square\ inches[/tex]
When minute hand moves 60 minutes, it makes one circle of area 397.77 square inches.
By using unitary method, we will calculate area swept by minute hand in 5 minutes:-
In 60 minutes, area swept = 397.77 square inches
In 1 minute, area swept = [tex]\frac{397.77}{60}[/tex]
In 5 minutes, area swept = [tex]\frac{397.77}{60}\times5=\frac{1988.85}{60} =33.15\ square\ inches[/tex]
Thus, the area swept out by the minute hand is 33.15 square inches when it moves 5 minutes.