Answer:
[tex]( - 1,1,3 )[/tex]
Step-by-step explanation:
Use the midpoint formula:
[tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}, \frac{z_1+z_2}{2} )[/tex]
We want to find the midpoint of the line
that has endpoints.
[tex](\frac{ - 6+4}{2},\frac{3+ - 1}{2}, \frac{4+2}{2} )[/tex]
We simplify to get;
[tex](\frac{ - 2}{2},\frac{2}{2}, \frac{6}{2} )[/tex]
This finally gives:
[tex]( - 1,1,3 )[/tex]
The correct answer is A.