Question

Un cilindro metálico está cerrado por un émbolo y contiene aire a 0 ºC y presión 912 mm Hg cuando el émbolo está a 50 cm del fondo del cilindro. Si a temperatura constante el émbolo se mantiene a 30 cm del fondo la presión del interior del cilindro es (1 atm = 760 mm Hg)

Answer 1

Answer:

Pressure inside the glass is 1520 mm Hg when it is at distance 30 cm from the base

Explanation:

As we know that here we have temperature constant condition is given

so we will have

$P_1V_1 = P_2V_2$

now we know that

$P_1 = 912 mmHg$

$V_1 = 50 cm$

$V_2 = 30 cm$

now we have

$(912)(50) = P(30)$

$P = 1520 mmHg$