A gardener is planting two types of trees: type A is three feet tall and grows at a rate of 15 inches per year. Type B is four feet tall and grows at a rate of 10 inches per year. Algibraically determine exactly how many years it will take for these trees to be the same height.

Respuesta :

Answer:

2.4 years

Step-by-step explanation:

We are given the following in the question:

12 inch = 1 foot

Type A tree:

It 3 feet(36 inches) tall and grows at a rate of 15 inches per year.

Thus, the height of tree type A will be given by the equation:

[tex]h_1(x) = 36 + 15x[/tex]

where x is the number of years.

Type B tree:

It 4 feet(48 inches) tall and grows at a rate of 10 inches per year.

Thus, the height of tree type B will be given by the equation:

[tex]h_2(x) = 48 + 10x[/tex]

where x is the number of years.

Let the two tree have equal height after n years, Thus, we can write:

[tex]h_1(n) = h_2(n)\\36 + 15n = 48 + 10n\\5n = 48-36\\5n = 12\\n = 2.4[/tex]

Thus, after 2.4 years the two types of tree will have same height.

Answer:

2.4 years

Step-by-step explanation:

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