Answer:
maximum kinetic energy is for Pulley
e) The pulley
Explanation:
Let 4 kg block is moving downwards with speed "v" so we can say that 2 kg block will move upwards with same speed "v"
Now we know that pulling is in pure rotational motion
so we will have
[tex]\omega = \frac{v}{R}[/tex]
[tex]\omega = \frac{v}{0.03}[/tex]
now kinetic energy of each is given as
For 4 kg block
[tex]K_1 = \frac{1}{2}(4)(v^2) = 2v^2[/tex]
for 2 kg block
[tex]K_2 = \frac{1}{2}(2)(v^2) = v^2[/tex]
For pulley
[tex]K_3 = \frac{1}{2}I\omega^2[/tex]
[tex]K_3 = \frac{1}{2}(4.5\times 10^{-3})\frac{(v^2)}{0.03^2}[/tex]
[tex]K_3 = 2.5 v^2[/tex]
So maximum kinetic energy is for Pulley