Newton's second law for rotational motion allows to find the results for the angular acceleration of the disk and the torque of force 3 are:
Given parameters
To find
Newton's second law for rotational motion states that torque is equal to the product of the moment of inertia times the angular acceleration
∑τ = I α
τ = F x r
Where the bold letters indicate vectors, τ is the torque, I the moment of inertia, α the angular acceleration, F the force and r the distance.
Torque is the vector magnitude has modulus and direction, the modulus can be found by developing the vector product
τ = F r sin θ
In general, for rotational movements, the reference system is placed in the turning point, in this case the axis of the disk and the positive direction is for counterclockwise turns, let's apply to this problem
Σ τ = F₁ R - F₂ d + F₃ 0 + F₄ d sin 53
Σ τ = 8.5 0.25 - 1.5 3.5 + 0 + 6.5 3.5 sin 53
Σ τ = 15.0 N m
As there is a net torque the disk is being accelerated, let's look for this angular acceleration
The moment of inertia of a disk is
I = ½ m r²
I = ½ 2.4 0.25²
I = 0.075 Kg m²
α = [tex]\frac{\sum \tau }{I}[/tex]
α = 15 / 0.075
α = 200 rad / s²
The expression for the torque of force 3 is
τ₃ = F₃ d₃ sin 45
τ₃ = F₃ sin 45 0
τ₃ = 0
In conclusion, using Newton's second law for rotational motion, we can find the angular acceleration of the disk and the torque of the force 3 are:
α = 200 rad / s²
τ₃ = F₃ d₃ sin 45 = 0
Learn more here: brainly.com/question/6855614
