Question

Need answer quick please
(I flipped the coins already)
Instructions In this experiment, you will be using two coins as a simulation for a real-world compound event. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.

1 What is the theoretical probability that the family has two dogs or two cats? Describe how to use two coins to simulate which two pets the family has.

Flip both coins 50 times and record your data in a table like the one below. Result Frequency Heads,

Heads Heads, 9

Tails Tails,26

Heads Tails,26

Tails 15

Total 50
Based on your data, what is the experimental probability that the family has two dogs or two cats?
If the family has three pets, what is the theoretical probability that they have three dogs or three cats?

How could you change the simulation to generate data for three pets?

please answer the questions Thank you for your help!!

Answer 1

Answer:

Step-by-step explanation:

1st coin   2nd coin                                 Total Outcomes   Possible HH or TT

H --           H or T              HH or HT

T --            H or T              TH or TT            4 = 2²                 1 + 1 = 2

probability: 2/4 = 0.5

3rd question: simulation   total outcomes 2³ = 8

possible get HHH or TTT: 2

probability 2/8 = 0.25

2nd question regarding experimental, the total 9 + 26 + 26 + 15 ≠ 50

Answer 2

Based on the data provided, the probabilities are as follows:

• Experimental probability of two dogs = 0.2
• Experimental probability of two cats = 0.28
• Theoretical probability of three dogs = 1/8
• Theoretical probability of three cats = 1/8

What is probability?

Probability is the likelihood or chance for a given event to occur or not occur.

• Probability = number of desired outcomes/number of possible outcomes

From the data provided:

Assuming;

• HH be two dogs = 10
• TT be two cats = 14
• HT be a dog and a cat = 13
• TH be a cat and a dog = 13
• Total = 50

Experimental probability of two dogs = 10/50 = 0.2

Experimental probability of two cats = 14/50 = 0.28

If the family has three pets:

sample space = 2^3 = 8

Let;

• Three dogs = HHH
• Three cats = TTT

Probability of HHH = 1/8

Probability of TTT = 1/8

To simulate for three pets, three coins are flipped.

Therefore, the probabilities are as follows:

• Experimental probably of two dogs = 0.2
• Experimental probably of two cats = 0.28
• Theoretical probability of three dogs = 1/8
• Theoretical probability of three cats = 1/8

Learn more about probability at: https://brainly.com/question/24756209