We need the value of [tex]a[/tex] from the first question. The initial thickness is 12mm, there "initial" means that the car has been driven for 0 kilometers. So, we know that
[tex]f(0)=12 \iff a\sqrt{120000-0}=12 \iff a=\dfrac{12}{\sqrt{120000}}=\dfrac{12}{200\sqrt{3}}[/tex]
Now, the second questions asks for the thickness after the car has driven 90000 km. So, we simply need to plug [tex]k=90000[/tex] in the equation to get
[tex]f(90000)=\dfrac{12}{200\sqrt{3}}\sqrt{120000-90000}=\dfrac{12}{200\sqrt{3}}\sqrt{30000}=\dfrac{12}{200\sqrt{3}}100\sqrt{3}=6[/tex]