solve the triangle, please help
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Answer:
Side A = 14; Side B = 24.25; Side C = 28 |
Angle A = 60 degrees; Angle B = 30 degrees; Angle C = 90 degrees
Step-by-step explanation:
Okay, I find this question a bit weird because you already have two sides
So, I'm going to assume:
Side A = 14
Side B = 24.25
Using Pythagoras theorem
[tex]a^2 + b^2 = c^2[/tex]
[tex]14^2 + 24.25^2 = c^2[/tex]
[tex]196 + 588.0625 = c^2[/tex]
[tex]c=\sqrt{784.0625}[/tex]
c = 28 units (28.00111605)
In the diagram, we can see there is a right angle triangle, and a little square
Therefore, we can say that Angle C is 90 degrees
Finding Angle A/B:
There are so many ways to find it, I'll just use this though
Using SOHCAHTOA
I'll be using the sine rule to find Angle B
[tex]sin =\frac{opposite}{hypotenuse}[/tex]
[tex]sin^-1 (\frac{14}{28} )[/tex]
Angle B = 30 degrees
The interior angles in a triangle add up to 180 degrees
Angle A = 180 - (90 + 30)
Angle A = 60 degrees
Verify:
60 + 30 + 90 = 180