Answer: C. 1.0 × 10^-11M
Explanation:
First Step: Determine the pOH of the solution by taking the -Log [-OH]
pOH = -Log (1.0 × 10^-3)
= 3
Second Step : Obtain the pH, using the following equation; pH + pOH = 14
pH + 3 = 14, making pH the subject of the formular we then have;
pH = 14 -3 = 11.
Last Step: Take the anti-log of the pH to get the concentration of H3O+.
∴ Anti-log of 11 = 1.0 × 10^-11M