Question

A 52.5-turn circular coil of radius 4.90 cm can be oriented in any direction in a uniform magnetic field having a magnitude of 0.465 T. If the coil carries a current of 26.3 mA, find the magnitude of the maximum possible torque exerted on the coil.

Answer 1

Answer:

The maximum possible torque is τ = $4.8 \times 10^{-3}$ N .

Explanation:

Given :

No. of turns $N = 52.5$

Radius of circular coil $r = 4.90 \times 10^{-2}$ m

Magnetic field $B = 0.465$ T

Current $I = 26.3 \times 10^{-3}$ A

For maximum torque,

 τ = $BIAN \sin \theta$

Where $A =$ area of coil $= \pi r^{2}$ = $75.39 \times 10^{-4}$

For maximum possible torque $\sin \theta = 1$,

    τ = $52.5 \times 26.3 \times 10^{-3} \times 0.465 \times 75.39 \times 10^{-4}$

    τ = $4.8 \times 10^{-3}$ N