Question

Suppose that 0.25 mole of gas C was added to
the mixture without changing the total pressure of
the mixture.
What is the partial pressure of C?​

Answer 1

Answer:

Pi = 0.25[P(TTL)/n(TTL)]

Explanation:

Let Total Pressure = P(TTL) and Total moles =n(TTL) => n(i)/n(TTL) = P(i)/P(TTL)

Given n(i) = 0.25 => Pi = 0.25[P(TTL)/n(TTL)]

Answer 2

Answer:

0.12 atm C

Explanation:

Edg 2020/21