Answer: 5.21, 4.69 & 10.1
Explanation:
Question 1 :
We have to determine the pOH of the solution first.
pOH = - Log [OH-]
= - Log ( 1.60 x 10∧-9)
= 9 - 0.204
= 8.79
Using the mathematical equation ;
pH + pOH = 14
∴ pH + 8.79 =14
Making pH subject of formular; pH = 14 - 8.79 = 5.21
Question 2:
pH = - Log [H3O+]
= - Log (2.00 x 10∧-5)
= 5 -0.301
= 4.69
Question 3:
Using the mathematical equation, pH + pOH = 14
3.90 +pOH = 14
∴ pOH = 14 -3.90
= 10.1
Answer:
1) pH = 5.20
2) pH = 4.70
3) pOH = 10.1
Explanation:
What is the pH of a solution with [OH- ] = 1.60x10-9 M?
Step 1: Data given
[OH-] = 1.60 * 10^-9 M
Step 2: Calculate pOH
pOH = -log[OH-]
pOH = -log [1.60*10^-9]
pOH = 8.80
Step 3: Calculate pH
pH = 14 - pOH
pH = 14 - 8.8 = 5.20
What is the pH of a solution if [H3O+] = 2.00x10-5 M?
[H3O+] = [H+] = 2.00 * 10^-5 M
pH = -log[H+]
pH = -log[2.00*10^-5]
pH = 4.70
A solution has a pH value of 3.90. What is the pOH for the solution?
pOH = 14 - pH
pOH = 14 -3.90 = 10.1
