Question

Dewayne missed four of the 30 problems on the problem set. What percent of the problems did Dewayne answer correctly? (answer with a fraction for the remainder)

Answer 1

Answer:

The percent of the problems did Dewayne answer correctly = 86.6%

Step-by-step explanation:

Given DeWayne missed four of the 30 problems on the problem set

let "E" be the event of missing problem set P(E) = $\frac{4}{30}$

Let $E^{-}$ be the event of DeWayne answer correctly

                                                        P($E^{-}$) = 1 - p(E)

                                                                   = $1- \frac{4}{30}$

                                                                    = $\frac{30-4}{30}$

                                                                    = $\frac{26}{30}$   = 0.866

The percent of the problems did Dewayne answer correctly = 86.6%