Question

The area of a rectangle is 35 m² in the length of rectangle is 3 m more than twice the width find the dimensions of the rectangle

Answer 1

Answer:

$Length=10 m\\\\Width=3.5 m$

Step-by-step explanation:

Area of the rectangle = $35 m^2$

Let the width of the rectangle be 'w' meter

Length of the rectangle=$(2w+3) meter$

Area of the rectangle = length * Width

$35=(2w+3)(w)\\\\35=2w^2+3w\\\\2w^2+3w-35=0$

Making the factors of the equation:

$2w^2+10w-7w-35=0$

Taking common form the equation:

$2w(w+5)-7(w+5)=0\\\\(w+5)(2w-7)=0$

$(w+5)=0\\\\w=-5$

OR

$2w-7=0\\\\2w=7\\\\w=7/2\\\\w=3.5m$

As, the width of the rectangle cannot be negative so the $width(w)= 3.5 m$

$Length(L)=2w+3= 2(3.5)+3= 7+3=10 m$

$Length=10 m\\\\Width=3.5 m$