Answer:
40% . The single reduction together is 40%.
Step-by-step explanation:
Let the bicycle cost is x before reduced price.
First 25% is reduced and again 20% further reduced.
Let the single reduction is y% if the two reduction together are equal.
Solution,
Case .1
reduction cost[tex]=x\times 25%[/tex]%
[tex]=x\times 25/100[/tex]
[tex]=x/4[/tex]
The cost of bicycle after reduction of 25% is
[tex]=x-x/4=3x/4[/tex]
cost of reduction further reduction of 20% [tex]=3x/4\times 20[/tex]%
[tex]=3x\times 20/(4\times 100)[/tex]
[tex]=3x/20[/tex]
The new cost of bicycle is further reduction of 20% is
[tex]=3x/4-3x/20[/tex]
[tex]=\left ( 15x-3x \right )/20[/tex]
[tex]=12x/20=3x/5[/tex]
Case.2
if single reduction is done new cost of cycle is equal
[tex]x-x\times y[/tex]%=[tex]3x/5[/tex]
[tex]x\left ( 1-y/100 \right )=3x/5[/tex]
[tex]\left ( 100-y \right )/100=3/5[/tex]
[tex]100-y=60[/tex]
[tex]y=40[/tex]%
single reduction of a cycle is 40%