Answer:
[H⁺] = 1×10⁻¹⁰ → Basic solution
Explanation:
For this question we need to know, the autoionization of water:
2H₂O (l) ⇄ H₃O⁺ (aq) + OH⁻(aq) Kw
Kw = 1ₓ10⁻¹⁴ → [H₃O⁺] . [OH⁻]
1ₓ10⁻¹⁴ /[OH⁻] = [H₃O⁺] → 1ₓ10⁻¹⁴ / 1×10⁻⁴ = 1×10⁻¹⁰
In order to determine if the solution is acidic, basic or neutral we use the pH value.
pH = - log [H₃O⁺] → -log 1ₓ10⁻¹⁰ = pH = 10 Basic solution
pH < 7 → Acidic solution
pH = 7 → Neutral solution
pH > 7 → Basic solution