Answer:
A charged particle moving in a constant magnetic field may experience a magnetic force but its speed will not change.
Explanation:
The magnetic force experienced by a charged particle q that moves in a magnetic field [tex]\vec{B}[/tex] with velocity [tex]\vec{v}[/tex] is:
[tex]\vec{F}=q\vec{v}\ x\ \vec{B}[/tex]
and its magnitude is given by:
[tex]F=q\ v \ B \sin \theta[/tex]
where [tex]\theta[/tex] is the angle between the magnetic field and the velocity.
There are two special cases:
The magnetic force is always perpendicular to the velocity. The work [tex]W[/tex] done by the magnetic force is equal to the force [tex]\vec{F}[/tex] multiplied by the displacement [tex]\vec{dr}[/tex] in the direction of the force:
[tex]W=\vec{F}.\vec{dr}=\vec{F}.(\vec{v}.\Delta t)=0[/tex]
Given that the work is equal to the change in kinetic energy [tex]W=\Delta K[/tex] and [tex]K \approx \frac{1}{2} mv^{2}[/tex] this means the speed will not change.