Question

Line K has a slope of -5. Line j is perpendicular to line k and passes through the point(5,9). Create the equation for line j

Answer 1

Answer:

j: y=1/5x+8

Step-by-step explanation:

k: m1=-5

j: m2=?(slope)

j: perpendicular to k,

then

m1*m2=-1

-5*m2=-1

m2=-1/(-5)

m2=1/5

A(5,9)... x1=5,y1=9

j: y-y1=m2(x-x1)

j: y-9=1/5(x-5)

j: y-9=1/5x-1/5*5

j: y-9=1/5x-1

j: y=1/5x-1+9

j: y=1/5x+8