Question

Have Retirement Benefits
Yes No
Men 275 50
Women 150 25

Suppose one employee is selected at random from these 500 employees. Compute the following probabilities. Provide your answers correct up to 2 decimal places.
(a) The probability of the intersection of events "man" and "yes".
(b) The probability of the intersection of events "no" and "man".
(c) Find the probability of the union of events "woman" or "no".

Answer 1

Answer:

(a) The probability of the intersection of events "man" and "yes" is 0.55.

(b) The probability of the intersection of events "no" and "man" is 0.10.

(c) The probability of the union of events "woman" or "no" is 0.45.

Step-by-step explanation:

The information provided is:

             Yes    No   Total

Men       275   50     325

Women  150   25      175

Total      425   75      500

(a)

Compute the probability that a randomly selected employee is a man and a has retirement benefits as follows:

$P(M\cap Y)=\frac{n(M\cap Y)}{N}=\frac{275}{500}=0.55$

Thus, the probability of the intersection of events "man" and "yes" is 0.55.

(b)

Compute the probability that a randomly selected employee does not have retirement benefits and is a man as follows:

$P(N\cap M)=\frac{n(N\cap M)}{N}=\frac{50}{500}=0.10$

Thus, the probability of the intersection of events "no" and "man" is 0.10.

(c)

Compute the probability that a randomly selected employee is a woman or has no retirement benefits as follows:

$P(W\cup N)=P(W)+P(N)-P(W\cap N)=\frac{175}{500}+\frac{75}{500}-\frac{25}{500}=0.45$

Thus, the probability of the union of events "woman" or "no" is 0.45.