Question

How do you put y=-3(x-4)^2-10 in standard form?

Answer 1

Answer:

y = -3x² + 24x - 58

Step-by-step explanation:

You distribute out the root and simply it.

y = -3(x-4)² - 10

y = -3(x² - 8x + 16) -10

y = -3x² + 24x - 48 - 10

y = -3x² + 24x - 58

Answer 2

Answer:

y=-3x^2 + 24x - 58

Step-by-step explanation:

You first distribute the -3 by multiplying it to x and -4. Then just add the exponent.