Question

Charges of −5.3 µC and +5.3 µC are separated by 4.2 cm. Find the electric force between them.

Answer 1

Answer:

Force between two charges is given as 143.3 N

Explanation:

As we know that electrostatic force between two point charges is given as

$F = \frac{kq_1q_2}{r^2}$

here we know that

$q_1 = -5.3 \mu C$

$q_2 = 5.3 \mu C$

also we know that

$r = 4.2 cm$

so we have

$F = \frac{(9\times 10^9)(5.3 \times 10^{-6})(5.3\times 10^{-6})}{0.042^2}$

so we have

$F = 143.3 N$