Question

how do i find the first term of a geometric sequence when i know a3= 1/8 and a6= 1 ?

Answer 1

Answer:

Step-by-step explanation:

nth term = ar^(n-1)

a3 = 1/8;   ar² = 1/8

a6 = 1;      ar⁵ = 1

$ar^{2}*r^{3}=1\\\\\frac{1}{8}*r^{3}=1\\\\r^{3}=1*8\\\\r^{3}=8\\\\r^{3}=2^{3}\\\\r=2$

$ar^{2}=\frac{1}{8}\\\\a*2^{2}=\frac{1}{8}\\\\a*4=\frac{1}{8}\\\\a=\frac{1}{8*4}\\\\a=\frac{1}{32}$