Hello I have a full sheet of homework but just a front so if you like to help me I would appreciate it!
Please do these ASAP.
![Hello I have a full sheet of homework but just a front so if you like to help me I would appreciate it Please do these ASAP class=](https://us-static.z-dn.net/files/dbb/9acb1de227ed8bf19145933686958f65.jpg)
![Hello I have a full sheet of homework but just a front so if you like to help me I would appreciate it Please do these ASAP class=](https://us-static.z-dn.net/files/d58/4e659865f530c841a9dbeb5aa8537b31.jpg)
![Hello I have a full sheet of homework but just a front so if you like to help me I would appreciate it Please do these ASAP class=](https://us-static.z-dn.net/files/df2/0b6fd8ad609b220caa12ddec79db02b6.jpg)
![Hello I have a full sheet of homework but just a front so if you like to help me I would appreciate it Please do these ASAP class=](https://us-static.z-dn.net/files/df9/b39f65ca7d0fe96ec0db5490309c9470.jpg)
Step-by-step explanation:
1 20.5-15.8=4.7
answer is D
2 D
because 0.03 equal to 3/100
3. A
perimeter of rectangle=length ×breath
=3/4 ×2/3
=1/2 inch
4
[tex] 1 \: \frac{4}{3} \: \: 2 \: \frac{6}{9} \: 3 \: \frac{8}{12} [/tex]
5 23
BODMAS
FIRST BRACKET
24+20÷4-(6)
SECOND DIVISION
24+5-6
THIRD ADDITION
29-6
FORTH SUBTRACTION
23