Question

You are given a bag with 10 balls, of which 3 are red, 3 are blue, 1 is yellow, 2 are black, and 1 is white. You pick one ball, note its color, put the ball back in the bag, and then pick another ball. The probability that it was the case that the first ball was black and the second ball was red is

Answer 1

Answer:

3/50

Step-by-step explanation:

P( 1st ball is a black ball) = number of black balls/ total balls

                    = 2/10 = 1/5

We put the ball back so we still have the same number of balls

P( 2nd ball is a red ball) = number of red balls/ total balls

                    = 3/10

P (1st ball black, 2nd red) = P( 1st ball is a black ball)* P( 2nd ball is a red ball)

                                          =1/5* 3/10

                                          = 3/50