Question

Help!!! 40 points!!!!

Write the equation of the line that is perpendicular to the line x+4y=2 and goes through the point (-2,6)

Answer 1

Step-by-step explanation:

x+4y = 2

4y= -x+2

$y = \frac{ - 1}{4} x + \frac{1}{2}$

slope of the above line = -1/4

The slope of the required line which is perpendicular to this line = 4

And, the required line also passes through(-2,6)

$\frac{y - 6}{x - ( - 2)} = 4$

$\frac{y - 6}{x + 2} = 4$

$y - 6 = 4(x + 2)$

$y - 6 = 4x + 8$

$4x + 8 - y + 6 = 0$

$4x - y + 14 =0$

The equation of the line that is perpendicular to the line x+4y=2 and goes through the point (-2,6)

4x-y+14=0

Answer 2

Answer:

-4x+y=14

Step-by-step explanation:

For it to be perpendicular, you need to switch the 1 before x and the 4 before y and chang the mark for one of them. Than you have -4x+y, substitute x and y for -2 and 6, you get 14