WPC Sports Company has noted that the size of individual "customer order" is normally distributed with a mean of $100 and a standard deviation of $12. If a soccer team of 16 players was to make the next batch of orders, what would be the standard error of the mean?

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Answer:

The standard error of the mean is 3.

Step-by-step explanation:

We are given that WPC Sports Company has noted that the size of individual "customer order" is normally distributed with a mean of $100 and a standard deviation of $12.

A soccer team of 16 players was to make the next batch of orders.

Since we know that the confidence interval is created by the given formula;

Suppose we have to calculate 95% confidence interval;

So, 95% Confidence interval = Sample mean [tex]\pm[/tex] Margin of error

where, Sample mean = [tex]\bar X[/tex] = $100

Margin of error = [tex]Z_\frac{\alpha}{2} \times \frac{\sigma}{\sqrt{n} }[/tex]

Here, [tex]\sigma[/tex] = standard deviation = $12

          n = sample of players = 16

So, Standard error formula is given by = [tex]\frac{\sigma}{\sqrt{n} }[/tex]

                                                                  = [tex]\frac{12}{\sqrt{16} }[/tex] = 3

Therefore, standard error of the mean for this sample is 3.

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