Question

The recessive allele b occurs with a frequency of 0.8 in a population of crabs that is in Hardy-Weinberg
equilibrium
What is the frequency of homozygous dominant individuals?
Choose 1 answer
0.8
0.64
0.04
0.32

Answer 1

Answer:0.04

Explanation:

Answer 2

"0.04" will be the the frequency of dominant individuals.

Given value is:

Recessive allele's frequency,

• b (q) = 0.8

Dominant allele's frequency,

• B (p) = $1-q$

                 = $1-0.8$

                 = $0.2$

Now,

The dominant individual's frequency will be:

= $p^2$

= $(0.2)^2$

= $0.04$

Thus the alternative i.e., "choice c" is right.

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