Respuesta :
Answer:
The stoichiometric coefficient for aluminum is 2
Explanation:
Step 1: Data given
Aluminum metal = Al(s)
aqueous iron(III) oxide = Fe2O3(s)
aqueous aluminum oxide = Al2O3(s)
iron metal = Fe(s)
Step 2: The unbalanced equation
Al(s) + Fe2O3(s) → Al2O3(s) + Fe(s)
Step 3: Balancing the equation
On the left side we have 1x Al , on the right we have 2x Al (in Al2O3). To balance the amount of Al on both sides, we have to multiply Al (on the left side) by 2.
2Al(s) + Fe2O3(s) → Al2O3(s) + Fe(s)
On the left side we have 2x Fe (in Fe2O3) , on the right we have 1x Fe. To balance the amount of Fe on both sides, we have to multiply Fe (on the right side) by 2. Now the equation is balanced.
2Al(s) + Fe2O3(s) → Al2O3(s) +2Fe(s)
The stoichiometric coefficient for aluminum is 2
The stoichiometric coefficient for aluminum when the chemical equation is balanced using the lowest, whole-number stoichiometric coefficients is 2
From the question,
We are to determine the stoichiometric coefficient for aluminum when the chemical equation for the reaction is balanced
The balanced chemical equation, using the lowest whole-number stoichiometric coefficient, for the reaction between aluminum metal and aqueous iron(III) oxide to form aqueous aluminum oxide and iron metal is
2Al(s) + Fe₂O₃(aq) → Al₂O₃(aq) + 2Fe(s)
Hence, the stoichiometric coefficient for aluminum when the chemical equation is balanced using the lowest, whole-number stoichiometric coefficients is 2
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