Answer:
Surface area of the whole figure[tex]= 320.28inch^2[/tex]
Step-by-step explanation:
The surface area of the figure :
Surface area of the cylinder(excluding top)+Surface area of the cone(excluding bottom)
Radius of the cylinder=3 inch and Height of cylinder=13 inch
Surface area of the cylinder with one circular face
[tex]=2\pi rh+\pi r^2[/tex]
As, [tex]\pi =\frac{22}{7}= 3.14[/tex]
[tex]=(2*3.14*3*13)+(3.14*3*3)\\\\=244.92+28.26\\\\=273.18inch^2[/tex]
Surface area of the cone excluding base:
[tex]=\pi *r*l[/tex]
l= slant height=5 inch r= radius= 3 inch
Surface area of the cone =[tex]3.14*3*5[/tex]
[tex]=47.1inch^2[/tex]
Total surface area of the whole figure[tex]=273.18+47.1[/tex]
[tex]= 320.28inch^2[/tex]
