Question

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $60. For one performance, 40 advance tickets and 15 same-day tickets were sold. The total amount paid for the tickets was $1525 . What was the price of each kind of ticket?

Answer 1

Answer:

Advance ticket = 25

Same-day ticket = 35

Step-by-step explanation:$From the question, x + y = 60...eq 1\\40x + 15y = 1525...eq 2\\x = 60 - y\\Substitute 60 - y for x in equation 2\\Hence, 40(60 - y) + 15y = 1525\\2400 - 40y + 15y = 1525\\2400 - 25y = 1525\\2400 - 1525 = 25y\\875 = 25y\\y = 35\\\\x + y = 60\\x + 35 = 60\\x = 60 - 35\\x = 25$