Answer:
10.07 L is the volume for the produced N₂
Explanation:
This is a question for the Ideal Gases Equation:
P . V = n . R . T
In STP conditions, the pressure is 1 atm and the T° is 273K
Let's determine the moles of produced N₂ by the decomposition of TNT
The reaction is:
2 C₇H₅(NO₂)₃ (s) → 7 C (s) + 7 CO (g) + 3 N₂ (g) + 5 H₂O (g)
We convert the mass to moles (mass / molar mass)
68.2 g . 1 mol / 227.13 g = 0.300 moles
Ratio is 2:3. 2 moles of TNT can produce 3 moles of N₂
Then, 0.300 moles will produce (0.300 . 3) / 2 = 0.450 moles
We replace data:
1 atm . V = 0.450 mol . 0.082 L.atm/mol.K . 273K
V = (0.450 mol . 0.082 L.atm/mol.K . 273K) / 1 atm
V = 10.07 L
