Question

1.00 mole of an ideal monoatomic gas at STP first undergoes isothermal expansion so that the volume at b is 2.5 times the volume at a. Next, heat is extracted at a constant volume so that the pressure drops. The gas is then compressed adiabatically back to the original state. Calculate the pressure at c.

Answer 1

Answer:

the pressure at c = 0.27 atm

Explanation:

Given that:

number of moles (n) = 1.0 moles

Value of gamma in the monoatomic gas (γ) = 5/3

During an isothermal expansion, the volume at b is = 2.5 times the volume at a ; this implies that:

$V_b = 2.5 V_a$

∴ To calculate  the pressure at c from a; the process is adiabatic compression; so we apply:

$P_aV_a^\gamma=P_cV_c^\gamma$

$\frac{P_c}{P_a}=[\frac{V_a}{V_c}]^{(2/3)$

$\frac{P_c}{1.0 atm}=[\frac{1}{2.5}]^{(2/3)$

$P_c=0.27 atm$

Thus, the pressure at c = 0.27 atm

Answer 2

The pressure at c should be 0.27 atm

Calculation of the pressure:

Since number of moles (n) = 1.0 moles

Value of gamma in the monoatomic gas (γ) = 5/3

Now

The pressure at c should be

$x\div 1.0 = (1 \div 2.5)^{2/3}$

x = 0.27 atm

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