Respuesta :
Answer:
The induced current is 0.084 A
Explanation:
the area given by the exercise is
A = 200 cm^2 = 200x10^-4 m^2
R = 5 Ω
N = 7 turns
The formula of the emf induced according to Faraday's law is equal to:
ε = (-N * dφ)/dt = (N*(b2-b1)*A)/dt
Replacing values:
ε = (7*(38 - 14) * (200x10^-4))/8x10^-3 = 0.42 V
the induced current is equal to:
I = ε /R = 0.42/5 = 0.084 A
Given Information:
Area of loop = A = 200 cm² = 0.0200 m²
Change in time = Δt = 8x10⁻³ seconds
Change in magnetic field = ΔB = (38x10⁻³ - 14x10⁻³) T
Number of turns = N = 7
Resistance of coil = R = 5 Ω
Required Information:
Induced current = I = ?
Answer:
Induced current = 0.084 A
Explanation:
From the Faraday's law the induced EMF ξ in the coil is given by
ξ = -NΔΦ/Δt
Where ΔΦ is the change in flux
ΔΦ = ΔBA
Where A is the area of the planer loop
ΔΦ = (38x10⁻³ - 14x10⁻³)*0.0200
ΔΦ = 0.00048
So the induced emf becomes
ξ = -NΔΦ/Δt
ξ = (-7*0.00048)/8x10⁻³
ξ = -0.42 V
The negative sign indicates that the induced emf opposes the change that produced it in the first place.
Finally, we can now find the induced current using Ohm's law
I = ξ/R
I = 0.42/5
I = 0.084 A
Therefore, the resulting induced current in the coil is 0.084 A
