Respuesta :
Answer:
This indicates that the chances of the mean life span today is greater than 70 years is 0.5871
Step-by-step explanation:
The past year showed an average life span of 71.8 years.
[tex]\mu = 71.8 years[/tex]
Population standard deviation = 8.9 years
[tex]\sigma = 8.9 years[/tex]
We are supposed to find the mean life span today is greater than 70 years
i.e. P(X>70)
Formula : [tex]Z = \frac{x-\mu}{\sigma}[/tex]
[tex]Z=\frac{70-71.8}{8.9}[/tex]
Z=−0.202
P(X<70)=0.4129
P(X>70)=1-P(X<70)=1-0.4129=0.5871
Hence This indicates that the chances of the mean life span today is greater than 70 years is 0.5871
Answer:
We conclude that the mean life span today is greater than 70 years.
Step-by-step explanation:
We are given that a random sample of 100 recorded deaths in the United States during the past year showed an average life span of 71.8 years. Assuming a population standard deviation of 8.9 years.
Let Null Hypothesis, [tex]\mu[/tex] [tex]\leq[/tex] 70 years {means that the mean life span today is less than or equal to 70 years}
Alternate Hypothesis, [tex]\mu[/tex] > 70 years {means that the mean life span today is greater than 70 years}
The test statistics that will be used here is One-sample z test statistics;
T.S. = [tex]\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
where, [tex]\bar X[/tex] = sample mean = 71.8 years
[tex]\sigma[/tex] = population standard deviation = 8.9 years
n = sample size = 100
So, test statistics = [tex]\frac{71.8 - 70}{\frac{8.9}{\sqrt{100} } }[/tex]
= 2.022
Now, since we are not given with significance level so we assume it to be 5%. At 5% significance level, the z table gives critical value of 1.96. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject null hypothesis as it fall in the rejection region.
Therefore, we conclude that the mean life span today is greater than 70 years.