Answer:
12.23m/s
Explanation:
Let's recall that
The Initial momentum in (East)axis = 900 x 15 which is = 13500 N-s
Initial momentum in (North) axis = 750 x 20 which is = 15000 N-s
Total initial momentum becomes = √[(13500)^2 + (15000)^2] = 20180.44 N-s
The initial momentum direction is at θ* East of North
Therefore, tanθ = 13500/15000 = 0.9 = tan42*
tanθ=42
The speed of the wreckage after collection is,
Recall that The law of momentum conservation states that
Momentum initial = Momentum final
20180.44 = (900+750) x v
v = 12.23 m/s
