Question

romine vapor in a 5.00-liter container at 300 K and 0.205 bar is to be heated to 340 K. Calculate the heat (kJ) that must be transferred to the gas to achieve the desired temperature increase, assuming that ˆ U Uˆ is independent of pressure.

Answer 1

Answer:

The heat required to raise the temperature Q = 78.7 J

Explanation:

Given data

Volume = 5 liter = 0.005 $m^{3}$

Pressure = 0.205 bar = 20.5 k pa

Initial temperature = 300 K

Final temperature = 340 K

specific heat = 0.473 $\frac{KJ}{kg K}$

Gas constant R = 0.082 $\frac{KJ}{kg K}$

From  the ideal gas equation

$P_{1 } V_{1}$ = m R $T_{1}$

Put all the values in above formula we get,

⇒ 20.5 × 0.005 = m × 0.082 × 300

⇒ m = 0.00416 kg

Heat required Q = m × C × ( $T_{2} - T_{1}$ )

⇒ Q = 0.00416 × 0.473 × ( 340 - 300 )

⇒ Q = 0.0787 KJ

⇒ Q = 78.7 J

This is the heat required to raise the temperature.