Respuesta :
Answer:
The rotor's angular velocity is 82.73rad/s
Explanation:
It is a curvilinear movement of a constant radius. If there is uniform angular acceleration, then it is a circular motion with constant acceleration, whose equations are analogous to that of the translational motion.
Calculating the initial velocity of the rotor, V1 in rad/s
V1 = 610rev/minute × 6.28 × 1miute/60secs
V1 = 63.85rad/s
Using kinematic equation to calculate the final velocity of the rotor
Given:
Angular acceleration = 5.9rad/s^2
Time,t= 3.2seconds
V2 = V1 + a × t
V2 = 63.85 + (5.9)× (3.2)
V2 = 63.85 + 18.88
V2 = 82.73rads/s
Answer:
Explanation:
Given:
wo = 610 rpm
To rad/s,
= 610 rpm ×2pi rad/60 s
= 63.88 rad/s
wf = 837 rpm
= 87.65 rad/s
ao = 5.9 rad/s^2
Using equations of circular motion,
wf = wo + aot
87.65 = 63.88 + 5.9×t
t = 4.025 s
Using the same equation,
At t = 3.2s (first 3.2 s of the motion),
wf = 63.88 + 5.9 × 3.2
= 82.76 rad/s
= 82.8 rad/s