Question

Write and equation for a parabola with x-intercepts (-3,0) and (5,0) which passes through the point (3,-48)

Answer 1

Answer:

Step-by-step explanation:

eq. of parabola through (-3,0) and (5,0) is

y=a(x+3)(x-5)

∵ (3,-48) lies on the parabola.

-48=a(3+3)(-48-5)

-48=6*-53 a

a=-48/(6×-53)=8/53

so eq. of parabola is

y=8/53(x+3)(x-5)

or y=8/53(x²+3x-5x-15)

or y=8/53(x²-2x-15)