Question

You push a 35 kg wooden box across a wooden floor at a constant speed of 1.0 m/s. The coefficient of kinetic friction is 0.16. Now you double the force on the box. How long would it take for the velocity of the crate to double to 2.0 m/s

Answer 1

Answer: t = 0.56s.

Explanation: please find the attached file for the solution

Answer 2

Answer:

Explanation:

Given:

Mass, M = 35 kg

Velocity, v1 = 1 m/s

Velocity, v2 = 2 m/s

Coefficient of friction, uo = 0.16

Total force = M × a

At constant velocity, a = 0

F - Fk = 0

F = Fk

= uo × M × g

= 35 × 9.8 × 0.16

= 54.9 N

At F2 = 2 × F1

= 109.8 N

F = M × a

But a = (v - u)/t

109.8 = 35 × (2 - 1)/t

t = 1 × 35/109.8

= 0.32 s