Respuesta :
Answer:
The dimensions of rectangular lot is Length=500 feet and Width=300 feet
Step-by-step explanation:
The formula for perimeter of rectangle is given by,
[tex] P=2L+2W[/tex]
Where, L = length, W = width and P = Perimeter.
According to given data, rectangular lot has a perimeter of 1600 feet. Therefore,
[tex] \therefore 1600=2L+2W[/tex] ….1
Now, cost of fencing along one length is given as $ 20 per feet. So total cost of one length is,
[tex] L\times \$\:20=\$\:20\:L[/tex]
Similarly, cost of fencing along two width is given as $ 5 per feet. So total cost of two width is,
[tex]2\:W \times \$\:5=\$\:10\:W [/tex]
Total cost of fencing along three sides is given as $13000. Therefore,
Total cost = Cost of fencing of one length + Cost of fencing of two width
Substituting the value,
[tex]\$\:13000 = \$\:20\:L + \$\:10\:W[/tex] ….2
So, there is two equations and two unknown. Solve it by substitution method.
Solving equation 1 for W.
Dividing both sides of equation by 2,
[tex]\therefore L+W=800 [/tex]
Subtracting L from both sides,
[tex]\therefore W=800-L[/tex] ….3
Substituting equation 3 into equation 1 and simplifying,
[tex]13000=20L+10\left ( 800-L \right )[/tex]
[tex]13000=20L+\left ( 8000-10L \right )[/tex]
[tex]13000=10L+8000[/tex]
[tex]13000-8000=10L[/tex]
[tex]5000=10L[/tex]
[tex]500=L[/tex]
So value of length is 500 feet. Substituting the value of L in equation 1 and simplifying,
[tex] 2L+2W=1600 [/tex]
[tex] 2\left ( 500 \right )+2W=1600 [/tex]
[tex] 1000+2W=1600 [/tex]
[tex] 2W=1600-1000 [/tex]
[tex] 2W=600 [/tex]
[tex] W=300[/tex]
So value of width is 300 feet.