Consider the following problem: A rectangular lot whose perimeter is 1600 feet is fenced along three sides. An expensive fencing along the lot's length costs $20 per foot. An inexpensive fencing along the two side widths costs only $5 per foot. The total cost of the fencing along the three sides comes to $13,000. What are the lot's dimensions

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Answer:

The dimensions of rectangular lot is Length=500 feet and Width=300 feet

Step-by-step explanation:

The formula for perimeter of rectangle is given by,  

[tex] P=2L+2W[/tex]

Where, L = length, W = width and P = Perimeter.  

According to given data, rectangular lot has a perimeter of 1600 feet. Therefore,  

[tex] \therefore 1600=2L+2W[/tex]   ….1

Now, cost of fencing along one length is given as $ 20 per feet. So total cost of one length is,  

[tex] L\times \$\:20=\$\:20\:L[/tex]

Similarly, cost of fencing along two width is given as $ 5 per feet. So total cost of two width is,  

[tex]2\:W \times \$\:5=\$\:10\:W [/tex]

Total cost of fencing along three sides is given as $13000. Therefore,  

Total cost = Cost of fencing of one length + Cost of fencing of two width

Substituting the value,

[tex]\$\:13000 = \$\:20\:L + \$\:10\:W[/tex]  ….2

So, there is two equations and two unknown. Solve it by substitution method.

Solving equation 1 for W.

Dividing both sides of equation by 2,  

[tex]\therefore L+W=800 [/tex]

Subtracting L from both sides,  

[tex]\therefore W=800-L[/tex]  ….3

Substituting equation 3 into equation 1 and simplifying,  

[tex]13000=20L+10\left ( 800-L \right )[/tex]  

[tex]13000=20L+\left ( 8000-10L \right )[/tex]  

[tex]13000=10L+8000[/tex]  

[tex]13000-8000=10L[/tex]  

[tex]5000=10L[/tex]  

[tex]500=L[/tex]  

So value of length is 500 feet. Substituting the value of L in equation 1 and simplifying,  

[tex] 2L+2W=1600 [/tex]  

[tex] 2\left ( 500 \right )+2W=1600 [/tex]  

[tex] 1000+2W=1600 [/tex]  

[tex] 2W=1600-1000 [/tex]  

[tex] 2W=600 [/tex]  

[tex] W=300[/tex]  

So value of width is 300 feet.  

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