(10) Chuck's coin box contains only pennies and
nickels. If he has 66 coins worth $2.38, how
many of each type of coin does he have?

Respuesta :

Answer:

Step-by-step explanation:

Set up two equations with the information given-- and things you know from experience: a penny is worth 1 cent and a nickel is worth 5 cents. $ 2.38 is 238 cents (so you can eliminate decimals for now)

Put those values into an equation about the total value:

p + 5n = 238

and you know the total number of coins is 66.

p + n = 66

get a value for p by "solving" (subtract n from both sides)

p = 66-n

Substitute that value for p in the first equation. Then solve.

(66 -n) + 5n = 238

4n = 238-66   Then isolate n by dividing both sides by 4

n = 172/4

n = 43  Substitute that in the second equation, then solve for p

p + 43 = 66      p = 66 - 43

p = 23

So Chuck has 23 pennies and 43 nickels